Exercise 1.10.
Here is another way of proving Lemma 1.6 (v). I do not claim that it is any simpler, but it introduces a useful idea.
(i) Show from first principles that, if an —»• a, then can —»• ca. (ii) Show from first principles that, if an —> a as n —> oo, then a2n —> a2. |
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